Find the inverse Laplace transform f(t) = ??{ F(s) } of the function F(s) = 8s / (s² - 1). f(t) = ??{ 8s / (s² - 1) } = ??{ 4 / (s + 1) + 4 / (s - 1) } =
Added by Jacob M.
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We want to find the inverse Laplace transform of F(s), which is f(t) = L^{-1}{F(s)}. To do this, we can rewrite F(s) as a sum of simpler functions whose inverse Laplace transforms are known. We can rewrite F(s) as: F(s) = (s^2 - 1) / 8s = (s^2 / 8s) - (1 / 8s) = Show more…
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