00:01
In this particular question we have given the figure in which the point charges are located at the corners of an equilateral triangle and given the length of side is 23 cm and we have to find the magnitude of electric field in newton per coulums and we have given a charge qa is 2 .4 nanoculum qb is minus 7 .4 nanoculum and qc is 1 .4 nanoculum.
00:29
So let's find out.
00:32
First of all, as we have to find out the electric field here, so we will just make a bisector in an equilateral triangle and so yeah, as this is the l and from this to this distance is d.
01:05
As equalateral triangle has an angle of 60 degrees each, so we can say this angle, this half angle is of 30 degrees.
01:20
From here we can find the value of cost theta.
01:31
Length is 23 centimeter or you can say 0 .23 meters or you can say d is equal to 0 .23 into cos of 30 degrees and 2 by 3.
01:49
Why 2 by 3? it is because it is the 2 third length of the full length of this bisector.
01:59
So we have multiplied it by 2 by 3.
02:02
From here we will get d is equal to 0 .1328 meters.
02:16
Now we will draw the vectors of electric field for qa.
02:21
Electric field vector is in this direction, ea.
02:25
And for qb electric field will be in this direction because it is negative and qc is in this direction and this is the shorter than even and e2 this is e3 because e3 why it is shorter because q3 is having smaller magnitude than both so now let's find out the electric fields e1 is equal to k k ua upon d square k is 9 into 10 this to power 9 qa is 2 .4 into 10 to 1 minus 9 coulum and d that we have find out is 0 .1328 meters square then the value of e1 is then e1 comes out to be e 1 224 .8 3 .6 newton per column.
03:46
Similarly for e2, 9 into 10x to power 9, qb is 7 .4 into 10 .5 minus 9 columns and d is the same 0 .1328 meter per square.
04:07
Then e2 will be 3776 .5806 newton per column...