00:01
I have drawn the direction of the electric fields at each position because the source charge is negative, all electric field point toward the source charge as i drew.
00:14
And now let's calculate the strength of the electric field for each position, for the position at the 0 .5 centimeter for the first position, we can tell that the distance from this position to the source charge is 5 times 10 to negative 2 meters.
00:40
And we calculate the strength of this electric field by using the formula k times the q divided by r square.
00:52
And we get the number 4 .3 times 10 to 4 newton per cooler.
00:58
And the direction of this electric field is pointing downward, which means it has a negative y component.
01:10
So we can rewrite this electric field in the component form, which is negative 4 .3 times 10 to 4 times the j unit vector newton perkunum.
01:27
And for the second position at negative 5 cm and 5 cm, the distance from this position to the source charge is the r2 equals to 5 times square root of 2 times 10 to negative 2 meters.
01:53
And we can calculate the magnitude of the electric field with the same formula, k times the absolute value of q divided by r2 square.
02:11
And we get the result is 2 .16 times 10 to 4 newton per cooler.
02:20
And then we can calculate the x and y component for the e2 as the x and y component the e2x and e2y have the same length.
02:41
So the e2x equals to e2y and they both equals to e2y...