00:01
I have drawn the directions of the electric fields at each position.
00:07
So our next step is to calculate the strengths of the electric field at each position and write the electric field in component form.
00:18
So let's first look at the electric field at the first position at the 5 cm, zero position.
00:28
And we can tell that the r here, the distance from this position to the source charge is 5 cm, which is 5 times 10 to negative 2 meters.
00:44
And we can calculate the strength of this electric field by using the formula 1 equals to 10 k times q divided by r square.
00:57
And we plug in all the numbers and get the result 4 .3 times 10 to 4 newtons per column.
01:07
And we can write this electric field in a component form, considering the direction of this electric field, which is 4 .3 times 1024 times the unit vector, newton per column.
01:30
And for the second position, negative 5 cm and 5 cm, the distance from this position to the source charge is 5 times square root of 2 times 10 to negative 2 meters.
01:54
And again, we calculate the strength of the electric field at this position by using the same formula.
02:04
And we can easily get the result is 2 .16 times 10 to 4 newton per cooler.
02:15
And to write this electric field in component form, we need to calculate the x component.
02:25
The e2x, e2x, as well as the y component, e2y, for this electric field...