10. The following probability table contains data relative to car accidents and weather conditions on a holiday weekend. \begin{tabular}{l|c|c|c} \hline & \begin{tabular}{c} Rain \\ \( (\boldsymbol{R}) \) \end{tabular} & \begin{tabular}{c} No rain \\ \( \left(\boldsymbol{R}^{\prime}\right) \) \end{tabular} & Total \\ \hline Accident \( (A) \) & 0.025 & 0.015 & 0.040 \\ No accident \( \left(A^{\prime}\right) \) & 0.400 & 0.560 & 0.960 \\ Total & 0.425 & 0.575 & 1.000 \\ \hline \end{tabular} Find the probability that a person chosen at random from the survey was in an accident, given that it was raining. Also find the probability that a person was not in an accident, given that it was not raining.
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- Probability of accident and rain, \( P(A \cap R) = 0.025 \) - Probability of rain, \( P(R) = 0.425 \) - Probability of no accident and no rain, \( P(A' \cap R') = 0.560 \) - Probability of no rain, \( P(R') = 0.575 \) Show more…
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