Question

Use a convergence test of your choice to determine whether the following series converges or diverges.\\ $\sum_{k=1}^{\infty} \frac{3k^4 + 1}{\sqrt[5]{k^8 + 6}}$ Select the correct choice below and fill in the answer box to complete your choice. A. The limit of the terms of the series is$\Box$. This is not 0, so the series diverges by the Divergence Test. B. The corresponding integral converges to$\Box$. Therefore, the series converges by the Integral Test. C. This series is a $p$-series with $p = \Box$. This is greater than 1, so the series converges. D. The limit of the terms of the series is$\Box$, so the series converges by the Divergence Test.

          Use a convergence test of your choice to determine whether the following series converges or diverges.\\
$\sum_{k=1}^{\infty} \frac{3k^4 + 1}{\sqrt[5]{k^8 + 6}}$
Select the correct choice below and fill in the answer box to complete your choice.
A. The limit of the terms of the series is$\Box$. This is not 0, so the series diverges by the Divergence Test.
B. The corresponding integral converges to$\Box$. Therefore, the series converges by the Integral Test.
C. This series is a $p$-series with $p = \Box$. This is greater than 1, so the series converges.
D. The limit of the terms of the series is$\Box$, so the series converges by the Divergence Test.

Use a convergence test of your choice to determine whether the following series converges or diverges.

∑k=1^∞(3k^4 + 1)/(√(k^8 + 6))
Select the correct choice below and fill in the answer box to complete your choice.
A. The limit of the terms of the series is. This is not 0, so the series diverges by the Divergence Test.
B. The corresponding integral converges to. Therefore, the series converges by the Integral Test.
C. This series is a p-series with p =. This is greater than 1, so the series converges.
D. The limit of the terms of the series is, so the series converges by the Divergence Test.

Added by Josep C.

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