The given equation is:
\(y'' + y' + 4y = 2\sinh{t}\)
Now, we find the homogeneous solution, \(y_h\). The characteristic equation for the homogeneous equation is:
\(r^2 + r + 4 = 0\)
Using the quadratic formula, we find the roots:
\(r = \frac{-1 \pm \sqrt{1^2
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