00:01
In the given question, we have to write the values of our thermodynamic constants.
00:04
So, in this, we first solve for path a, which is our reversible.
00:10
So, for path a, the reversible part, we know that over here, the delta h or the enthalpy will be 0.
00:20
Why? because it is an isothermal process.
00:24
Because it is an isothermal process, the change in temperature will also be 0.
00:29
So now when we know that the work done there are two formula in terms of pressure and temperature and volume so it is minus nrt log v final upon v initial and that is equal to the negative of nrt log pressure initial upon pressure final because pressure and volume have an inverse relationship so so the formula also changes accordingly.
00:58
So when we put the values over here, this will be worked on is equal to 1 into 8 .314 into 8 .314, the value of gas constant, into log 1 by 300 kelvin in terms of temperature.
01:13
So this comes out to be minus 2 .74 into 10 to the power 3 joules...