Question

10.5 A Pelton wheel to be designed is to run at 300 rpm under an effective head of 150 m. The ratio of the nozzle diameter to the pitch circle diameter is 1/12. Assuming efficiency = 84%, $C_v$ = 0.98 and speed ratio = 0.45, determine (a) the diameter of the wheel, (b) diameter of the jet (c) the quantity of water flow (d) the minimum number of buckets required; and (e) the power developed. [Ans. (a) 1.55 m, (b) 0.129 m, (c) 0.694 $m^3$/s, (d) 21 (e) 858 kW]

          10.5 A Pelton wheel to be designed is to run at 300 rpm under an effective head of 150 m.
The ratio of the nozzle diameter to the pitch circle diameter is 1/12. Assuming efficiency
= 84%, $C_v$ = 0.98 and speed ratio = 0.45, determine (a) the diameter of the wheel,
(b) diameter of the jet (c) the quantity of water flow (d) the minimum number of buckets
required; and (e) the power developed.
[Ans. (a) 1.55 m, (b) 0.129 m, (c) 0.694 $m^3$/s, (d) 21 (e) 858 kW]

10.5 A Pelton wheel to be designed is to run at 300 rpm under an effective head of 150 m.
The ratio of the nozzle diameter to the pitch circle diameter is 1/12. Assuming efficiency
= 84%, $Cv$ = 0.98 and speed ratio = 0.45, determine (a) the diameter of the wheel,
(b) diameter of the jet (c) the quantity of water flow (d) the minimum number of buckets
required; and (e) the power developed.
[Ans. (a) 1.55 m, (b) 0.129 m, (c) 0.694 m^3/s, (d) 21 (e) 858 kW]

Added by Kayla L.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Narayan Hari

01/27/2025

Step 1

\[ V = C \cdot \sqrt{2 \cdot g \cdot H} \] Where: - $ C = 0.98 $ - $ g = 9.81 \, \text{m/s}^2 $ - $ H = 150 \, \text{m} $ \[ V = 0.98 \cdot \sqrt{2 \cdot 9.81 \cdot 150} \] \[ V = 0.98 \cdot \sqrt{2943} \] \[ V \approx 0.98 \cdot 54.24 \] \[ V \approx 53.15 Show more…

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10.5 A Pelton wheel to be designed is to run at 300 rpm under an effective head of 150 m. The ratio of the nozzle diameter to the pitch circle diameter is 1/12. Assuming efficiency = 84%, Cv = 0.98, and speed ratio = 0.45, determine (a) the diameter of the wheel, (b) diameter of the jet (c) the quantity of water flow (d) the minimum number of buckets required; and (e) the power developed. [Ans. (a) 1.55 m, (b) 0.129 m, (c) 0.694 m^3/s, (d) 21 (e) 858 kW]