We are given that $\frac{dV}{dt} = 8$ cubic feet per minute, and the diameter is three times the altitude, so $2r = 3h$, which means $r = \frac{3}{2}h$.
The volume of a cone is given by $V = \frac{1}{3}\pi r^2 h$. Substituting $r = \frac{3}{2}h$, we get
$V =
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