Question

[11]. (12 points) Sketch the graph of $h(x)$ below using the following information. $h(-3) = 2$, $h(-1) = -1$, and $h(2) = -1$. $\lim_{x \to -\infty} h(x) = +\infty$, and $\lim_{x \to \infty} h(x) = 2$. $h'(x) = 0$, at $x = -3$ and $x = 1$. $h''(x) = 0$, at $x = -3$, $x = -1$ and $x = 2$. $h'(x) > 0$, on the interval $(1, \infty)$. $h'(x) < 0$, on the interval $(-\infty, -3)$ and $(-3, 1)$. $h''(x) > 0$, on the interval $(-\infty, -3)$ and $(-1, 2)$. $h''(x) < 0$, on the interval $(-3, -1)$ and $(2, \infty)$. Interval Curve $f'(x)$ $f''(x)$

          [11]. (12 points) Sketch the graph of $h(x)$ below using the following information.
$h(-3) = 2$, $h(-1) = -1$, and $h(2) = -1$.
$\lim_{x \to -\infty} h(x) = +\infty$, and $\lim_{x \to \infty} h(x) = 2$.
$h'(x) = 0$, at $x = -3$ and $x = 1$.
$h''(x) = 0$, at $x = -3$, $x = -1$ and $x = 2$.
$h'(x) > 0$, on the interval $(1, \infty)$.
$h'(x) < 0$, on the interval $(-\infty, -3)$ and $(-3, 1)$.
$h''(x) > 0$, on the interval $(-\infty, -3)$ and $(-1, 2)$.
$h''(x) < 0$, on the interval $(-3, -1)$ and $(2, \infty)$.
Interval
Curve
$f'(x)$
$f''(x)$

[11]. (12 points) Sketch the graph of h(x) below using the following information.
h(-3) = 2, h(-1) = -1, and h(2) = -1.
limx → -∞ h(x) = +∞, and limx →∞ h(x) = 2.
h'(x) = 0, at x = -3 and x = 1.
h”(x) = 0, at x = -3, x = -1 and x = 2.
h'(x) > 0, on the interval (1, ∞).
h'(x) < 0, on the interval (-∞, -3) and (-3, 1).
h”(x) > 0, on the interval (-∞, -3) and (-1, 2).
h”(x) < 0, on the interval (-3, -1) and (2, ∞).
Interval
Curve
f'(x)
f”(x)

Added by Emily N.

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