11. The position (as a function of time) of a simple harmonic oscillator is given by x(t) = (9.0m) cos(?/3 t) where t is in seconds. What is the maximum acceleration of this oscillator? A) ? m/s² B) 2? m/s² C) ?² m/s² D) 3?² m/s² E) 3? m/s²
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Step 1: The maximum acceleration of a simple harmonic oscillator is given by the formula \(a_{\text{max}} = \omega^2 \cdot A\), where \(A\) is the amplitude of the motion and \(\omega\) is the angular frequency of the motion. Show more…
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Prabhu R.
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