The position of a simple harmonic oscillator is given by x(t)=2 cos (?/6 t) in (m) where t is in seconds. What is the maximum acceleration of the oscillator? 7.3 m/s^2 1.5 m/s^2 0.54 m/s^2 2.34 m/s^2
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In this case, the given position function is x(t) = 2 cos((π/6)t). To find the maximum acceleration, we need to differentiate the position function twice with respect to time. First, let's find the velocity function by differentiating x(t) once: v(t) = dx(t)/dt Show more…
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