(1.12) $$ \int \frac{x-1}{\sqrt{x^2 - 4x + 3}} dx $$ I
Added by David C.
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Then $du = dx$. Also, $x = u+2$. Substitute these into the integral: $$ I = \int \frac{(u+2)-1}{\sqrt{u^2 - 1}} du = \int \frac{u+1}{\sqrt{u^2 - 1}} du $$ Now, we can split the integral into two parts: $$ I = \int \frac{u}{\sqrt{u^2 - 1}} du + \int Show more…
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