We want to find an expression for $w = a^{-1}ba(cb)^{-1}$.
First, let's find $(cb)^{-1}$. Since $(ab)^{-1} = b^{-1}a^{-1}$, we have $(cb)^{-1} = b^{-1}c^{-1}$.
Now, let's substitute this into the expression for $w$:
$w = a^{-1}ba(cb)^{-1} =
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