00:01
So in this problem, we are given a cone that is bounded between the plane z equals zero, which is the x and y plane z equals 1, which is up here.
00:09
So z here is a function of x and y, which is equal to the square root of x squared plus y squared.
00:14
So if we find, say, for example, f's of x, that's going to be x divided by the square of x squared plus y squared, and f's of y is equal to y divided by the square root of x squared plus y squared.
00:28
And in our case, the area of s is going to equal to the double integral over r of the square root of ffx squared plus f of y squared plus 1.
00:42
The a, when the region here is obtained by projecting s onto the x and by plane, and we get that the region r is just going to be a disk or radius of radius 1.
00:53
The area for this region.
00:55
Here is pi because the radius is 1, so pi are squared, r equals 1 here, we give us the area of it to be pi...