Consider the series. sum_{n=2}^infty x^{ln n} (a) Determine the convergence or divergence of the series for x = 1. converges diverges (b) Determine the convergence or divergence of the series for x = 1/e. converges diverges (c) Find the positive values of x for which the series converges. (Enter your answer using interval notation.) (-infty, 1/e)
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It seems like there is a typo in the question, but I assume the series is given by: $$\sum_{n=1}^{\infty} \frac{x^n}{n}$$ (a) To determine the convergence or divergence of the series for $x=1$, we have: $$\sum_{n=1}^{\infty} \frac{1^n}{n} = \sum_{n=1}^{\infty} Show moreā¦
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