00:01
Okay, so in this question we have the following setup.
00:05
We've got a 10 metre long beam, and after two metres we have a reaction force ra.
00:16
We've got an 8 -killanuton force down at the start.
00:21
Then there's another 1 metre, and we have this 12 -killan -furton force.
00:29
And then two meters after that we have this block here, which has a weight of six kiloons per meter and extends for five meters.
00:45
So the other half of the block.
00:47
But three meters into that, we have another reaction force rb.
00:54
And then this is the final two meters.
00:56
So this whole system is in equilibrium.
00:59
So first of all, let's replace this with this block with a force from its center of mass.
01:10
So we can replace this.
01:11
So six kiloons per meter gives an overall force of six times five is 30 kiloons.
01:19
And this is going to be applying from the center of maths.
01:28
So this is going to be, so after 2 .5 meters, we're going to have a force here of 30...