12. The number of arrangements of 6 children in a line, if 3 of them (the triplets) must stand together: 13. The number of permutations of the word FLOWER where the F and L are not together is:
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So, we have 10 entities (7 individual children + 1 group of triplets) to arrange in a line. The number of arrangements is then 10!. For the second question, let's consider the cases where F and L are together and subtract it from the total number of permutations Show more…
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