Question

12. Which of the following gives the antiderivatives of $\frac{1 - x^2}{(1 + x^2)^2}$? (a) $\frac{x}{1 + x^2} + C$ (b) $\frac{1}{1 + x^2} + C$ (c) $\frac{1 - x}{1 + x^2} + C$ (d) $\frac{1}{(1 + x^2)^2} + C$ (e) $\frac{x}{(1 + x^2)^2} + C$

          12. Which of the following gives the antiderivatives of $\frac{1 - x^2}{(1 + x^2)^2}$?
(a) $\frac{x}{1 + x^2} + C$
(b) $\frac{1}{1 + x^2} + C$
(c) $\frac{1 - x}{1 + x^2} + C$
(d) $\frac{1}{(1 + x^2)^2} + C$
(e) $\frac{x}{(1 + x^2)^2} + C$

12. Which of the following gives the antiderivatives of (1 - x^2)/((1 + x^2)^2)?
(a) (x)/(1 + x^2) + C
(b) (1)/(1 + x^2) + C
(c) (1 - x)/(1 + x^2) + C
(d) (1)/((1 + x^2)^2) + C
(e) (x)/((1 + x^2)^2) + C

Added by Jessica A.

Calculus: Early Transcendentals

James Stewart 8th Edition

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02/23/2023

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Step 1: The antiderivative of (1+2) is given by integrating the function with respect to the variable x. Show more…

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12.Which of the following gives the antiderivatives of (1+222 (a) 1 1-r (b) 0+z+t (c) +c 1+x2 T (o) o++1) d 1

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