Question

$\begin{aligned} f(x) = \begin{cases} \frac{x^2 - 1}{x - 1}, & x \neq 1 \\ 3, & x = 1 \end{cases} \end{aligned}$ Which of the following is a TRUE statement about the given function? The limit of the function as $x \to 1$ is 3, corresponding with the point shown in the graph. The limit of the function as $x \to 1$ is "DNE" corresponding with the hole shown in the graph.

          $\begin{aligned} f(x) = \begin{cases} \frac{x^2 - 1}{x - 1}, & x \neq 1 \\ 3, & x = 1 \end{cases} \end{aligned}$
Which of the following is a TRUE statement about the given function?
The limit of the function as $x \to 1$ is 3, corresponding with the point shown in the graph.
The limit of the function as $x \to 1$ is "DNE" corresponding with the hole shown in the graph.

f(x) = (x^2 - 1)/(x - 1), x ≠ 1
3, x = 1
Which of the following is a TRUE statement about the given function?
The limit of the function as x → 1 is 3, corresponding with the point shown in the graph.
The limit of the function as x → 1 is "DNE" corresponding with the hole shown in the graph.

Added by Carla R.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

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Step 1

First, let's simplify the given function: 13x - X1 x - 1 3, x - 1 AN We can rewrite it as: 13x - x - 1, x - 1 Show more…

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13x - X1 x - 1 3, x - 1 AN Which of the following is a TRUE statement about the given function? taetmitoftheluncbaesk-ai.c The limit of the function as x - 1 is DNE corresponding with the hole shown in the graph.