Question

13-16 Calculate $\frac{dr}{d\tau}$ by the chain rule, and then check your result by expressing $r$ in terms of $\tau$ and differentiating. 13. $r = t i + t^2 j$; $t = 4\tau + 1$ 14. $r = (2\cos t, \sin t)$; $t = \ln \tau$

Name: 13 16 calculate fracdrdtau by the chain rule and then check your result by expressing r in terms of tau and differentiating 13 r t i t2 j t 4tau 1 14 r 2cos t sin t t ln tau 12668
Uploaded: 2020-08-29T18:35:09-08:00
Duration: 1 min 49 s
Channel: Zachary Mitchell
Description: 13 16 calculate fracdrdtau by the chain rule and then check your result by expressing r in terms of tau and differentiating 13 r t i t2 j t 4tau 1 14 r 2cos t sin t t ln tau 12668

          13-16 Calculate $\frac{dr}{d\tau}$ by the chain rule, and then check your result by expressing $r$ in terms of $\tau$ and differentiating.
13. $r = t i + t^2 j$; $t = 4\tau + 1$
14. $r = (2\cos t, \sin t)$; $t = \ln \tau$

$13 16 calculate fracdrdtau by the chain rule and then check your result by expressing r in terms of tau and differentiating 13 r t i t2 j t 4tau 1 14 r 2cos t sin t t ln tau 12668$

Added by Patricia S.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Zachary Mitchell

08/29/2020

Step 1

We want to find $\frac{dr}{d\tau}$. By the chain rule, $\frac{dr}{d\tau} = \frac{dr}{dt} \frac{dt}{d\tau}$. Show more…

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13-16 Calculate $\frac{dr}{d\tau}$ by the chain rule, and then check your result by expressing $r$ in terms of $\tau$ and differentiating. 13. $r = t i + t^2 j$; $t = 4\tau + 1$ 14. $r = (2\cos t, \sin t)$; $t = \ln \tau$