00:01
Hi, here for the given question we need to calculate the area in the region of the first quadrant bounded by xy is equal to 1, xy is equal to 4, y is equal to x and y is equal to 2x using the appropriate change of the variable.
00:16
So here let u is equal to xy and v is equal to y.
00:21
So here in our case we can determine the range of u and v corresponding to the first quadrant.
00:27
So here in our case we know that u is equal to xy which is equal to x square which is greater than or equal to 0.
00:34
Now, similarly v is equal to y which is also greater than or equal to 0 which implies v is equal to 2x greater than or equal to 0.
00:43
So here now further we know that xy is equal to 1 we have u equals to 1 and v equals to 1 similarly we have xy is equal to 4 which will give us u equals to 4 and v equals to 4.
00:56
So here from this value further we can say that here we have y is equal to x which implies x is equal to v.
01:04
This is x, x equals to v and y equals to 2x implies x is equal to v by 2.
01:10
So here in our case we have limit of u as 0 less than or equal to u less than or equal to 4 and for v by 2 less than or equal to x less than or equal to v.
01:21
So here area a can be written as integration over region r da...