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13. DETAILS MY NOTES ASK YOUR TEACHER Find the first partial derivatives of the function. $f(x, y, z) = x^9yz^2 + 2yz$ $f_x(x, y, z) =$ $f_y(x, y, z) =$ $f_z(x, y, z) =$

Name: 13 details my notes ask your teacher find the first partial derivatives of the function fx y z x9yz2 2yz fxx y z fyx y z fzx y z 76004
Uploaded: 2023-08-02T18:30:51-08:00
Duration: 2 min 53 s
Channel: Sri K
Description: 13 details my notes ask your teacher find the first partial derivatives of the function fx y z x9yz2 2yz fxx y z fyx y z fzx y z 76004

          13.
DETAILS
MY NOTES
ASK YOUR TEACHER
Find the first partial derivatives of the function.
$f(x, y, z) = x^9yz^2 + 2yz$
$f_x(x, y, z) =$
$f_y(x, y, z) =$
$f_z(x, y, z) =$

Added by Lorenzo T.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Sri K

08/02/2023

Step 1

Step 2: Find $f_x(x, y, z)$. To find the partial derivative with respect to $x$, we treat $y$ and $z$ as constants. $f_x(x, y, z) = \frac{\partial}{\partial x}(x^9yz^2 + 2yz)$ For the term $x^9yz^2$, the derivative with respect to $x$ is $9x^{9-1}yz^2 = Show more…

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13. DETAILS MY NOTES ASK YOUR TEACHER Find the first partial derivatives of the function. $f(x, y, z) = x^9yz^2 + 2yz$ $f_x(x, y, z) =$ $f_y(x, y, z) =$ $f_z(x, y, z) =$