00:01
In this problem, we are given a data that is x is equal to 1, x is equal to 2 and x is equal to 3.
00:11
And vertical side we have y is equal to 1 and y is equal to 3 and the value is 0 .1, 0 .2, 0 .1 and 0 .1 .3.
00:28
Now, the total of these terms will become 0 .3, 0 .3 and 0 .4.
00:41
And this side, total of the y, and this is equal to x, and it becomes 0 .4 and 0 .6, which is equal to 1.
00:55
Now, if x is equal to 1, then probability of x is 0 .4.
01:08
If x is equal to 2, then probability is 0 .6.
01:16
Then x will be 1 multiply 0 .4 plus 2 multiply 0 .6, which is 0 .4 plus 1 .2, which is 0 .4 plus 1 .2 is equal to 1 .6.
01:33
For y, that is, py, it becomes 1, 0 .3 and 2, 0 .6, 3, 0 .4.
01:48
Then ey will be 0 .3 plus 0 .6 multiply 2 plus 0 .4 multiply 3, then it becomes 0 .3 plus 0 .4 multiply 3.
02:04
1 .2 plus 1 .2, then it will be 2 .7.
02:11
Now, we have to calculate in first part, e, x, y, that is summation of xy, px is equal to x and y is equal to y.
02:29
Then it will be 0 plus 0 plus 0 plus 0 plus 0 plus 0 .1 plus 0 .2, which is equal to 0 .3.
02:40
Therefore, we can say exy is equal to 0 .3.
02:48
Now, in second part, we have to calculate variance of x and variance of y...