13.183 A point P moves along the spiral path $r = (0.1)\theta$ ft, where $\theta$ is in radians. The angular position $\theta = 2t$ rad, where t is in seconds, and $r = 0$ at $t = 0$. Determine the magnitudes of the velocity and acceleration of P at $t = 1$ s. Problem 13.183
Added by Steve D.
Close
Step 1
The velocity of a point moving in polar coordinates is given by the formula: v = r' + rθ' where r' is the derivative of r with respect to θ, and θ' is the derivative of θ with respect to time. Show more…
Show all steps
Your feedback will help us improve your experience
Sufiyan Alam and 72 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A particle is moving along a circular path with a radius of 0.005 km. The angular position of the particle is a function of time as given here: ̘ = 0.5t^2 + 2t. After 2 seconds: a. Find the centripetal acceleration. b. Find the tangential acceleration. c. The total acceleration.
Sufiyan A.
A particle moves outward along spiral . Its trajectory if given by r=Aθ where A is a constant. A = 1 π m/rad. θ increases in time according to θ = αt2 2 a. show that radial acceleration is zero when θ = 1/ 2^0.5 . rad. b. at what angle do the radial and tangential acceleration are equal
Timothy J.
A point $P$ moves in counter-clockwise direction on a circular path as shown in figure. The movement of $P$ is such that it sweep out a length $s=t^{3}+5$, where $s$ is in metres and $t$ is in seconds. The radius of the path is $20 \mathrm{~m}$. The acceleration of $P$ when $t=2 \mathrm{~s}$ is nearly [AIEEE 2010] (a) $14 \mathrm{~m} / \mathrm{s}^{2}$ (b) $13 \mathrm{~m} / \mathrm{s}^{2}$ (c) $12 \mathrm{~m} / \mathrm{s}^{2}$ (d) $7.2 \mathrm{~m} / \mathrm{s}^{2}$
Projectile Motion
Round 2
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD