00:01
Hello students hope you are doing great in this question we are given this reaction and we have to find out the mechanism for the formation of these two products.
00:10
So let us see the mechanism for this reaction.
00:15
Starting with the starting material that we are given here is a dine like this we have two dines.
00:24
In the first case first step we have proton here.
00:28
The double bond acts as levis acid so it will donate its electron to the proton and the proton.
00:34
Can attach at this carbon and also at this carbon.
00:38
So by attacking it one carbon at a time there will be formation of two intermediates.
00:43
That is that is there will be formation of two carboket ions.
00:47
In the first step, the first intermediate the carbokatin formation takes place at this carbon.
00:53
And in the second, carbokatin formation takes place at the terminal carbon like this.
01:03
So let us consider for this intermediate first.
01:08
Let's name that as 1 and 2.
01:11
So for the first intermediate, here we have the first intermediate like this.
01:16
We have positive charge over here.
01:19
And in the next step, it reacts with b.
01:21
So this b.
01:22
Minus will attack here.
01:23
The pi electrons will move here and they will fulfill this positive charge.
01:29
So the product that we have here is like this.
01:32
We are double bond over here and this positive charge is satisfied here.
01:39
So this is our first product that is formed in the reaction.
01:43
Let us take the second intermediate.
01:45
So after taking the second intermediate, we have double bond over here and positive charge on this terminal carbon.
01:57
So this is secondary carbocatin and here we have one hydrogen.
02:00
So if we do the one two rearrangement, the positive charge will shift here...