Question

*1.36 A problem was posed as follows: The equation for the velocity of a fluid stream measured with a Pitot tube is $v = \sqrt{\frac{2\Delta p}{\rho}}$ where $v$ = velocity $\Delta p$ = pressure drop $\rho$ = density of fluid If the pressure drop is 15 mm Hg, and the density of the fluid is 1.20 g/cm³, calculate the velocity in ft/s. The solution given was $\frac{2}{1} \left| 15 \text{ mmHg} \times \frac{1.013 \times 10^5 \text{ Pa}}{760 \text{ mm Hg}} \times \frac{1 \text{ N}}{1 \text{ Pa}} \times \frac{10^3 (\text{g})(\text{cm})}{(1 \text{ N})(\text{s}^2)} \times \frac{(\text{cm}^2)}{1.20 \text{ g}} \times \left( \frac{1 \text{ m}}{100 \text{ cm}} \right)^2 \right|$ $= \left[ 33322.4 \frac{\text{cm}^2}{\text{s}^2} \right]^{1/2} = 182.5 \frac{\text{cm}}{\text{s}}$ Check that the answer is correct by (a) Repeating the calculations but carrying them out in reverse order starting with the answer. (b) Consolidating the units and making sure the final set of units are correct.

          *1.36 A problem was posed as follows:
The equation for the velocity of a fluid stream measured with a Pitot tube is
$v = \sqrt{\frac{2\Delta p}{\rho}}$
where $v$ = velocity
$\Delta p$ = pressure drop
$\rho$ = density of fluid
If the pressure drop is 15 mm Hg, and the density of the fluid is 1.20 g/cm³, calculate the velocity in ft/s. The solution given was
$\frac{2}{1} \left| 15 \text{ mmHg} \times \frac{1.013 \times 10^5 \text{ Pa}}{760 \text{ mm Hg}} \times \frac{1 \text{ N}}{1 \text{ Pa}} \times \frac{10^3 (\text{g})(\text{cm})}{(1 \text{ N})(\text{s}^2)} \times \frac{(\text{cm}^2)}{1.20 \text{ g}} \times \left( \frac{1 \text{ m}}{100 \text{ cm}} \right)^2 \right|$ 
$= \left[ 33322.4 \frac{\text{cm}^2}{\text{s}^2} \right]^{1/2} = 182.5 \frac{\text{cm}}{\text{s}}$
Check that the answer is correct by
(a) Repeating the calculations but carrying them out in reverse order starting with the answer.
(b) Consolidating the units and making sure the final set of units are correct.

*1.36 A problem was posed as follows:
The equation for the velocity of a fluid stream measured with a Pitot tube is
v = √((2Δ p)/(ρ))
where v = velocity
Δ p = pressure drop
ρ = density of fluid
If the pressure drop is 15 mm Hg, and the density of the fluid is 1.20 g/cm³, calculate the velocity in ft/s. The solution given was
(2)/(1)| 15 mmHg×(1.013 × 10^5 Pa)/(760 mm Hg)×(1 N)/(1 Pa)×(10^3 (g)(cm))/((1 N)(s^2))×((cm^2))/(1.20 g)×( (1 m)/(100 cm))^2 |
= [ 33322.4 (cm^2)/(s^2)]^1/2 = 182.5 (cm)/(s)
Check that the answer is correct by
(a) Repeating the calculations but carrying them out in reverse order starting with the answer.
(b) Consolidating the units and making sure the final set of units are correct.

Added by Mackenzie S.

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