00:01
Hello, the question is taken from calculus and the question is if f x is equal to having this value, then find the absolute maximum of f x is equal to minus 2 .1.
00:12
Fx is given to us that is equal to x cube plus 2x square plus x plus 2 and we need to find a minima at minus 2 .1.
00:29
So f prime x will be equal to 3x square plus 4x plus 1.
00:37
So in order to evaluate the value of maxima, we need to keep it is equal to 0.
00:41
So 3x square plus 4x plus 1 is equal to 0.
00:46
So this implies 3x square plus 3x plus x plus x plus 1 is equal to 0, which will gives us the value 3x plus 1 and x plus 1 is equal to 0.
00:59
So x 1 value of x is minus 1 by 3 and x is equal to minus 1.
01:05
So let me check which one is the minimum value.
01:08
So by differentiating it we get 6x plus 4.
01:14
So when we substitute the value of minus 1 by 3, so we get minus 2 plus 4 is equal to 2.
01:20
So that will give us the value of minima...