00:01
In this problem, we have been given d prime p, and we need to find the demand function d of p.
00:07
Now, what we want to do is find the demand function.
00:11
Now, how can we obtain that? we can obtain that by integrating d prime p.
00:17
That's the derivative of d of p.
00:19
We integrate this with respect to p.
00:21
So we need to integrate negative 2 500 divided by p squared.
00:28
So what can we do? we write this as negative 2 -5 -00 times p -to -the -power of negative 2.
00:35
And then we take out the constant negative -250 -5 -0, and then this is what we get.
00:43
So now what we do is we use the power rule of integrals.
00:48
Using that, the integral of p -to -the -power of negative 2 will be p -to -the -power of negative 2 plus 1 divided by negative 2 plus 1.
00:55
And with this, we add an arbitrary constant.
00:58
So we have negative 2 .5 .0 times p to the power of negative 1 divided by negative 1.
01:05
And with this, we add c.
01:08
So negative 2 .5 .00 divided by negative 1 is just 2 5 .00...