Question

14. Find the average rate of change of \( f(x)=\sin x \ln x \) on the interval \( 1 \leq x \leq a \). \[ \ln a c=\frac{f(a)-f(1)}{a-1}=\frac{\sin a \ln a-0}{a-1} \quad \sin (1) \ln (1)=0 \]

          14. Find the average rate of change of \( f(x)=\sin x \ln x \) on the interval \( 1 \leq x \leq a \).
\[
\ln a c=\frac{f(a)-f(1)}{a-1}=\frac{\sin a \ln a-0}{a-1} \quad \sin (1) \ln (1)=0
\]

14. Find the average rate of change of f(x)=sin x ln x on the interval 1 ≤ x ≤ a.

ln a c=(f(a)-f(1))/(a-1)=(sin a ln a-0)/(a-1) sin (1) ln (1)=0

Added by Karen F.

Precalculus

Michael Sullivan 9th Edition

Chapter 6

Instant Answer

Solved by Expert Joseph Lentino

07/07/2020

Step 1

The function is \( f(x) = \sin x \ln x \). The interval is \( 1 \leq x \leq a \). Show more…

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14. Find the average rate of change of \( f(x)=\sin x \ln x \) on the interval \( 1 \leq x \leq a \). \[ \ln a c=\frac{f(a)-f(1)}{a-1}=\frac{\sin a \ln a-0}{a-1} \quad \sin (1) \ln (1)=0 \]