00:01
All right, solution in a, the y over d x, is y square e negative 3x, so the y over y square, e negative 3x, d negative 3x, d .e, negative 3x, d x.
00:17
So if we integrate plus i, negative 1 over y, this is integral e negative 3x, d x, which is e negative 3x, negative 1 over 3 e, plus c.
00:34
Therefore, y, we take rasi prokof, balsi, is negative.
00:46
So 1 over e negative x over 3 minus some c.
00:56
Now y 0 is when iq 0, which is 1 over 1 over 3 minus c, and this is equal to 1.
01:05
1 3 minus 0 is 1...