00:01
Hello students, first we have to find u x v .u equals to 0.
00:06
So, u x v .u equals to u2v3 minus u3v2 into u1 plus u3v1 minus u1v3 into u2 plus u3 into u1v2 minus u2v1.
00:31
So, expanding the dot product, we get u1u2v3 minus u1u3v2 plus u2u3v1 minus u2u1v3 plus u3u1v2 minus u2v1u3.
00:57
Notice that the terms in the dot product cancel each other out.
01:02
So, u x v .u equals to 0.
01:06
Therefore, u x v is orthogonal to u.
01:16
Similarly, we can see that u x v .v is equals to 0.
01:26
So, we can say that u x v is orthogonal to vector view.
01:35
Now, the next part is to show that the line, the two lines intersect at exactly one point.
01:44
We need to find the values of t and s for which the two lines have the same point of intersection.
01:50
So, set the coordinates of the two lines equal to each other.
01:55
For the x coordinate, 3 minus 5t equals to 7 plus 3s.
02:00
For the y coordinate, 7 plus 2t equals to 5 minus s.
02:07
For the z coordinate, 4 minus t equals to 10 minus 2s.
02:12
Now, we solve the system of equation.
02:14
So, this implies s equals to 5t minus 4 by 3.
02:21
This implies t equals to minus 10 by 11.
02:29
Now, substitute the value into t, s equals to minus 94 by 33.
02:39
Now, we have to find the points of intersection by plugging the values of t and s.
02:47
So, using the first equation to find the x coordinate, x equals to 3 minus 5t...