150 minutes remaining 31 of 31 questions remaining Exam Content Question 1 Question 1 2.5 Points If the anticodon on tRNA is GAC (tyrosine) (5' -> 3'), the sequence of the 5' -> 3' template strand of the gene in mRNA that specifies this amino acid is AUG. TAC. GUC. CTG.
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You may want to reference (Pages 737-742) Section 21.5 while completing this problem. The following sequence is a portion of the DNA template strand: 3' GCT ATA CCA AAA 5' Codons in mRNA: The Genetic Code for Amino Acids First letter Second letter Third letter U C A G U UUU Phe (F) UCU Ser (S) UAU Tyr (Y) UGU Cys (C) U UUC Phe (F) UCC Ser (S) UAC Tyr (Y) UGC Cys (C) C UUA Leu (L) UCA Ser (S) UAA STOP UGA STOP A UUG Leu (L) UCG Ser (S) UAG STOP UGG Trp (W) G C CUU Leu (L) CCU Pro (P) CAU His (H) CGU Arg (R) U CUC Leu (L) CCC Pro (P) CAC His (H) CGC Arg (R) C CUA Leu (L) CCA Pro (P) CAA Gln (Q) CGA Arg (R) A CUG Leu (L) CCG Pro (P) CAG Gln (Q) CGG Arg (R) G A AUU Ile (I) ACU Thr (T) AAU Asn (N) AGU Ser (S) U AUC Ile (I) ACC Thr (T) AAC Asn (N) AGC Ser (S) C AUA Ile (I) ACA Thr (T) AAA Lys (K) AGA Arg (R) A AUG START/Met (M) ACG Thr (T) AAG Lys (K) AGG Arg (R) G G GUU Val (V) GCU Ala (A) GAU Asp (D) GGU Gly (G) U GUC Val (V) GCC Ala (A) GAC Asp (D) GGC Gly (G) C GUA Val (V) GCA Ala (A) GAA Glu (E) GGA Gly (G) A GUG Val (V) GCG Ala (A) GAG Glu (E) GGG Gly (G) G Part B What are the anticodons of the tRNAs for the mRNA in Part A? Enter your answer as a string without dashes, using one-letter abbreviations for bases. Submit Request Answer Part C Enter the three-letter abbreviations for this segment in the peptide chain. Enter your answer as a string without dashes or commas, using three-letter abbreviations for amino acids. Submit Request Answer Part D Enter the one-letter abbreviations for this segment in the peptide chain. Enter your answer as a string without dashes or commas, using one-letter abbreviations for amino acids. Submit Request Answer
Jackson M.
Fill-in-the-blank: The anticodon which matches the sequence CAA would be: QUESTION 17 A sequence of DNA is: 5' TAC TGA CCG 3' Using the sequence and the codon chart, answer the following: 1. What mRNA sequence would result after transcription? 2. What amino acid sequence would result from translation? *Make sure to number your answers* Universal Genetic Code Chart Messenger RNA Codons and Amino Acids for Which They Code
Adi S.
A portion of the template strand of a gene is provided below: 5 ' - ATGACAAACGAT - 3 ' Answer the following questions about this DNA template. a. Provide the sequence of the portion of the mRNA that would be produced upon transcription of this DNA template. Provide single-letter nucleotide code in the 5' to 3' direction (do not use spaces or extra characters). 5'UACUGUUUGCU b. Assuming that translation begins starting from the first nucleotide, what amino acid sequence would be encoded by the portion of the mRNA transcribed in part (a)? Provide the single-letter amino acid code starting from the amino (N) terminus and proceeding toward the carboxyl (C) terminus (do not use spaces or extra characters). (N)YCLL c. What is the anticodon sequence from the tRNA that decodes the first codon in the portion of the mRNA that was transcribed in part (a)? Provide the anticodon sequence that forms three canonical (Watson-Crick) base pairs with the codon using single-letter nucleotide code in the 5' to 3' direction (do not use spaces or extra characters). 5'ACA3'
Sri K.
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