00:01
In this question, we have to solve the given equation y dash plus 6y plus 9 times integral 0 to t y of tau d tau equals to 1 with the condition that y0 is equal to 1.
00:16
Okay, so first of all we consider let p of t equals to integral 0 to t y tau d tau.
00:27
Correct.
00:27
From this we get p dash of t will be simply y of t.
00:34
Correct.
00:36
So here we have y 0 equals to 1.
00:41
We get p 0 equals to 0 and p dash 0 equals to 1.
00:47
Okay.
00:47
Okay, so hence the equation 1, let's say, so equation 1 will be given by y dash, it will be p double dash plus 6y, that is 6p dash plus 9 times of p equals to 1.
01:08
This will be the required equation.
01:12
Corresponding auxiliary equation we can write.
01:16
Auxiliary equation will be given by m square plus 6m plus 9 equals to 0.
01:27
This is m plus 3 whole square we get two repeated root minus 3 and minus 3.
01:35
So we get the corresponding homogeneous solution as the complementary function which we say pct of t it will be c1 t plus c2 e raised to minus 3 times of t...