16. Let \( f(x)=(\arccos x)-3 x . \quad \frac{-u}{\sqrt{1-u^{2}}} \) a.) Find \( f^{\prime}(x) \). \[ f^{\prime}(x)=-\frac{1}{\sqrt{1-x^{2}}}-3 \] b.) Find the equation of the tangent line to \( f(x) \) at the point where \( x=0 \).
Added by Gregg M.
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The derivative of \(\arccos x\) is \(-\frac{1}{\sqrt{1-x^2}}\). The derivative of \(-3x\) is \(-3\). So, \( f'(x) = -\frac{1}{\sqrt{1-x^2}} - 3 \). Show more…
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