00:01
In this problem, we are given five different generic reactions, and we want to predict how the system will be affected if we increase the pressure for each one of these reactions.
00:12
You are told that each one of them takes place inside of a cylinder with a movable piston.
00:18
So therefore, that means that the volume can change as we change the pressure.
00:23
And so the disturbance that we are imposing on each one of these systems is an increase in pressure.
00:31
Which means a decrease in volume.
00:35
And so according to la shatlier's principle, in order to respond to that change of an increase in pressure, the system will decrease the pressure in order to reestablish equilibrium.
00:50
And the way that we decrease the pressure is by forming fewer moles of gas.
00:57
And the reason for that is that gases exert pressure on the inside of the walls of that container.
01:07
Solids and liquids do not exert any pressure.
01:10
And so, therefore, we have to examine for each one of the given reactions how many moles of gas there are on each side of the reaction.
01:20
And then we know that the reaction will shift to the side that forms the fewest number of moles of gas, so that way the pressure can be minimized.
01:30
So starting with part a, we look and we see that both of the species involved are solids.
01:38
And so because there are no gases, the equilibrium, the system will not shift either way in order to reestablish equilibrium, because only solid species are participating.
01:54
So an increase in the pressure will have no effect on the equilibrium of this reaction...