Question

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. The acceleration function (in m/s²) and the initial velocity v(0) are given for a particle moving along a line. a(t) = 2t + 4, v(0) = -12, 0 ? t ? 6 Find the velocity at time t. Step 1 The velocity function is the antiderivative of the acceleration. v(t) = ?(2t + 4) dt = t² + 4t + C Step 2 We must determine the value of C. We know that v(0) = -12. Substituting 0 into our antiderivative gives -12 = v(0) = 0 + C. Therefore, C = -12.

          This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part.

The acceleration function (in m/s²) and the initial velocity v(0) are given for a particle moving along a line.
a(t) = 2t + 4, v(0) = -12, 0 ? t ? 6

Find the velocity at time t.

Step 1
The velocity function is the antiderivative of the acceleration.
v(t) = ?(2t + 4) dt = t² + 4t + C

Step 2
We must determine the value of C. We know that v(0) = -12.
Substituting 0 into our antiderivative gives -12 = v(0) = 0 + C. Therefore, C = -12.

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part.

The acceleration function (in m/s²) and the initial velocity v(0) are given for a particle moving along a line.
a(t) = 2t + 4, v(0) = -12, 0 ? t ? 6

Find the velocity at time t.

Step 1
The velocity function is the antiderivative of the acceleration.
v(t) = ?(2t + 4) dt = t² + 4t + C

Step 2
We must determine the value of C. We know that v(0) = -12.
Substituting 0 into our antiderivative gives -12 = v(0) = 0 + C. Therefore, C = -12.

Added by Carmen S.

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