Question

17. An object is thrown straight up with a velocity, in ft/s, given by v(t) = -32t + 64, where t is in seconds, from a height of 48 feet. (a) What is the object's maximum velocity? (b) What is the object's maximum displacement? (c) When does the maximum displacement occur? (d) When will the object reach a height of 0? (Hint: find when the displacement is -48ft.)

          17. An object is thrown straight up with a velocity, in ft/s, given by v(t) = -32t + 64, where t is in seconds, from a height of 48 feet.

(a) What is the object's maximum velocity?
(b) What is the object's maximum displacement?
(c) When does the maximum displacement occur?
(d) When will the object reach a height of 0? (Hint: find when the displacement is -48ft.)

17. An object is thrown straight up with a velocity, in ft/s, given by v(t) = -32t + 64, where t is in seconds, from a height of 48 feet.

(a) What is the object's maximum velocity?
(b) What is the object's maximum displacement?
(c) When does the maximum displacement occur?
(d) When will the object reach a height of 0? (Hint: find when the displacement is -48ft.)

Added by Sherry B.

Calculus: Early Transcendentals

James Stewart 8th Edition

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06/14/2023

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17. An object is thrown straight up with a velocity, in ft/s, given by v(t) = -32t + 64, where t is in seconds, from a height of 48 feet: (a) What is the object's maximum velocity? (b) What is the object's maximum displacement? (c) When does the maximum displacement occur? (d) When will the object reach a height of 0? (Hint: find when the displacement is -48ft.)