00:01
As for the question we solve this question for the diagram.
00:09
This is top event.
00:12
This is connected from a gate.
00:15
This is gate a.
00:20
This is divided into two gates.
00:27
This is gate b.
00:31
And this is gate c.
00:36
The gate b is also divided in two parts.
00:41
And gate c is also divided in two parts.
00:50
5, 6, 7.
00:53
This is mu1 and the mu1 value is 2 .25.
00:58
This is mu2 and the value is 0 .35.
01:03
This is mu3 and the value is 0 .55.
01:08
And the value of mu4 equals to 1 .5.
01:15
So, we can see we know reliability of each sums.
01:23
Then r1 equals to e minus r1t.
01:31
So, the total reliability is total reliability r1 equals to e minus 0 .25.
01:41
1 equals to 0 .778.
01:47
And r2 equals to e minus r2t equals to e minus 0 .35 into 1 equals to 0 .7046.
02:02
Then value of r3 equals to e minus r3t equals to e minus 0 .55 into 1 equals to 0 .5769.
02:17
And the value of r4, reliability of r4 is e minus r4t equals to e minus 1 .5 into 1 equals to 0 .223.
02:34
And then we know reliability of the top event can be determined as r equals to 1 minus t...