Question

1 pt What is the magnitude of the force on an electron at that distance? (in N) 3. A $1.83 \times 10^{-8}$ B $2.66 \times 10^{-8}$ C $3.86 \times 10^{-8}$ D $5.59 \times 10^{-8}$ E $8.11 \times 10^{-8}$ F $1.18 \times 10^{-7}$ G $1.70 \times 10^{-7}$ H $2.47 \times 10^{-7}$

          1 pt
What is the magnitude of the force on an electron at that
distance?
(in N)
3.
A $1.83 \times 10^{-8}$
B $2.66 \times 10^{-8}$
C $3.86 \times 10^{-8}$
D $5.59 \times 10^{-8}$
E $8.11 \times 10^{-8}$
F $1.18 \times 10^{-7}$
G $1.70 \times 10^{-7}$
H $2.47 \times 10^{-7}$

1 pt
What is the magnitude of the force on an electron at that
distance?
(in N)
3.
A 1.83 × 10^-8
B 2.66 × 10^-8
C 3.86 × 10^-8
D 5.59 × 10^-8
E 8.11 × 10^-8
F 1.18 × 10^-7
G 1.70 × 10^-7
H 2.47 × 10^-7

Added by Amanda S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Mkhitar Hobosyan

Step 1

The electric field is given by the equation: E = k * (Q / r^2) where k is the electrostatic constant (9 x 10^9 Nm^2/C^2), Q is the charge of the proton (1.6 x 10^-19 C), and r is the distance between the proton and the electron (1.5 x 10^-10 m). Plugging in the Show more…

Show all steps

Thanks for your feedback!

What is the magnitude of the force on an electron at that distance? (in N) 3. A 1.83 x 10^-8 B 2.66 x 10^-8 C 3.86 x 10^-8 D 5.59 x 10^-8 E 8.11 x 10^-8 F 1.18 x 10^-7 G 1.70 x 10^-7 H 2.47 x 10^-7