1the spring force is a variable force since it becomes...

The spring force is a variable force since it becomes larger as the spring is stretched or compressed from equilibrium. What is the basic relation between the x component of the spring force Fx, the spring constant k, and the displacement from equilibrium Δx = x-xeq? Fx = -k Fx = kx^2/2 Fx = -k(x-xeq) Fx = +k(x-xeq)

Nonconforming Spring A certain spring is found $n o t$ to conform to Hooke's law. The force (in newtons) it exerts when stretched a distance $x$ (in meters) is found to have magnitude $(52.8 \mathrm{~N} / \mathrm{m}) x+\left(38.4 \mathrm{~N} / \mathrm{m}^{2}\right) x^{2}$ in the direction opposing the stretch. (a) Compute the work required to stretch the spring from $x_{1}=0.500$ $\mathrm{m}$ to $x_{2}=1.00 \mathrm{~m} .$ (b) With one end of the spring fixed, a particle of mass $2.17 \mathrm{~kg}$ is attached to the other end of the spring when it is extended by an amount $x_{2}=1.00 \mathrm{~m}$. If the particle is then released from rest, what is its speed at the instant the spring has returned to the configuration in which the extension is $x_{1}=0.500 \mathrm{~m} ?(\mathrm{c})$ Is the force exerted by the spring conservative or nonconservative? Explain.

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