00:01
Hi here for the given question.
00:03
We are given that we have matrix a which is equal to 1 2 1 2 4 2 again 1 2 1.
00:18
Now here we need to calculate the eigenvalues eigenvector and then we need to verify whether s inverse a s is equal to diagonal matrix or not.
00:28
So here first of all, we will find the eigenvalues for that.
00:31
We will take determinant of a minus lambda i which is equal to 1 minus lambda 2 1 2 4 minus lambda 2 1 2 1 minus lambda.
00:42
So simplifying this further here we have minus lambda cube plus 6 lambda square which can be again written as here we have this determinant equals to 0.
00:54
So here our equation will be minus lambda square multiplied with lambda minus 6 is equal to 0.
01:00
So here the eigenvalues are 0 0 and 6.
01:08
Now further corresponding to each eigenvalues we need to calculate eigenvector using the equation ab is equal to lambda b.
01:18
So here using this equation we can find the eigenvector as for lambda is equal to 0 we have eigenvector v1 is equal to minus 2 1 and 0.
01:28
Whereas another eigenvector which is minus 1 0 1.
01:32
Whereas for lambda is equal to 6 we have eigenvector v3 equals to here in our case eigenvector v3 is 1 2 1...