Question

2. [-/3 Points] DETAILS HRW10 24.P.008. MY NOTES PRACTICE ANOTHER A graph of the x component of the electric field as a function of x in a region of space is shown in the figure below. The scale of the vertical axis is set by $E_{xs} = 50.0$ N/C. The y and z components of the electric field are zero in this region. Suppose that the electric potential at the origin is 18 V. $E_x$ (N/C) $E_{xs}$ 0 $-E_{xs}$ 1 2 3 4 5 6 x (m) (a) What is the electric potential at x = 2.0 m? V (b) What is the greatest positive value of the electric potential for points on the x axis for which $0 \le x \le 6.0$ m? V (c) For what value of x is the electric potential zero? m Submit Answer MY NOTES PRACTICE ANOTHER 3. [-/2 Points] DETAILS HRW10 24.P.011. A nonconducting sphere has radius $R = 2.88$ cm and uniformly distributed charge $q = +4.50$ fC. Take the electric potential at the sphere's center to be $V_0 = 0$. (a) What is V at radial distance $r = 1.45$ cm? V (b) What is V at radial distance $r = R$? V

          2. [-/3 Points]
DETAILS
HRW10 24.P.008.
MY NOTES
PRACTICE ANOTHER
A graph of the x component of the electric field as a function of x in a region of space is shown in the figure below. The scale of the vertical axis is set by $E_{xs} = 50.0$ N/C. The y and z components of
the electric field are zero in this region. Suppose that the electric potential at the origin is 18 V.
$E_x$ (N/C)
$E_{xs}$
0
$-E_{xs}$
1 2 3 4 5 6
x (m)
(a) What is the electric potential at x = 2.0 m?
V
(b) What is the greatest positive value of the electric potential for points on the x axis for which $0 \le x \le 6.0$ m?
V
(c) For what value of x is the electric potential zero?
m
Submit Answer
MY NOTES
PRACTICE ANOTHER
3. [-/2 Points]
DETAILS
HRW10 24.P.011.
A nonconducting sphere has radius $R = 2.88$ cm and uniformly distributed charge $q = +4.50$ fC. Take the electric potential at the sphere's center to be $V_0 = 0$.
(a) What is V at radial distance $r = 1.45$ cm?
V
(b) What is V at radial distance $r = R$?
V
        
Show more…
2. [-/3 Points]
DETAILS
HRW10 24.P.008.
MY NOTES
PRACTICE ANOTHER
A graph of the x component of the electric field as a function of x in a region of space is shown in the figure below. The scale of the vertical axis is set by Exs = 50.0 N/C. The y and z components of
the electric field are zero in this region. Suppose that the electric potential at the origin is 18 V.
Ex (N/C)
Exs
0
-Exs
1 2 3 4 5 6
x (m)
(a) What is the electric potential at x = 2.0 m?
V
(b) What is the greatest positive value of the electric potential for points on the x axis for which 0 ≤ x ≤ 6.0 m?
V
(c) For what value of x is the electric potential zero?
m
Submit Answer
MY NOTES
PRACTICE ANOTHER
3. [-/2 Points]
DETAILS
HRW10 24.P.011.
A nonconducting sphere has radius R = 2.88 cm and uniformly distributed charge q = +4.50 fC. Take the electric potential at the sphere's center to be V0 = 0.
(a) What is V at radial distance r = 1.45 cm?
V
(b) What is V at radial distance r = R?
V

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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HRW10 24.P.008. MY NOTES PRACTICE ANOTHER A graph of the x component of the electric field as a function of x in a region of space is shown in the figure below. The scale of the vertical axis is set by Exs = 50.0 N/C. The y and z components of the electric field are zero in this region. Suppose that the electric potential at the origin is 18 V. E, (N/C) x (m) (a) What is the electric potential at x = 2.0 m? (b) What is the greatest positive value of the electric potential for points on the x axis for which 0 ≤ x ≤ 6.0 m? (c) For what value of x is the electric potential zero? Submit Answer HRW10 24.P.011. MY NOTES PRACTICE ANOTHER A nonconducting sphere has radius R = 2.88 cm and uniformly distributed charge q = +4.50 fC. Take the electric potential at the sphere's center to be Vc = 0. (a) What is V at radial distance r = 1.45 cm? (b) What is V at radial distance r = R?
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Transcript

-
00:02 Alright, so we have been given that the electric field e is equal to let me call that k, 1 by 4 by epsilon equals to k and qx upon x squared plus a squared power 3 by 2.
00:23 Now to find the maximum value of e, we need to differentiate this e with respect to x to find out the position where he will be maximum so this and equate this to zero right so this implies kq times one upon x squared plus a square by two minus three x by two two x upon x squared plus a squared 5 by 2 using the product rule for differentiation okay kk goes to the other side and become 0 similarly we can take 1 upon x squared plus a square power 3 by 2 common so 1 will be on the left side left term and on the right term will be a 3x squared upon x squared plus a square and this is now equal to 0 now solving for x gives me x is equal to plus minus a upon root 2 and with the question that says a is equal to 10 centimeters that is 0 .1 meter this gives me x is equal to plus minus 7 .07 c and plus and minus denotes the two sides of the ring where the electric field will be 0 okay so now let's move on to part v so in part this is part a.
02:22 Now for part b, we need to calculate electric field and find the graph of the electric field.
02:30 Now, so to find the graph, i have drawn the graph in excel.
02:38 Let me take this out here.
02:44 So here is the graph that i drew on excel, microsoft excel...
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