2. 4 Al (s) + 3 O2 (g) ? 2 Al2O3 (s) Determine the mass of aluminum oxide that is produced from 0.280 moles of aluminum and 0.250 moles of oxygen? Al = 0.280 moles O = 0.250 moles
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To determine the limiting reactant, we need to calculate the moles of Al2O3 that can be produced from each reactant. From the balanced chemical equation, we see that 4 moles of Al react with 3 moles of O2 to produce 2 moles of Al2O3. Therefore, the mole ratio of Show more…
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Ma Ednelyn L.
Aluminum oxide forms when aluminum reacts with oxygen. Balance the following chemical equation: 2 Al + 3 O2 -> 2 Al2O3. Given that 62.79 g of aluminum metal is allowed to react, how many moles of aluminum is this? Next, we need to determine how many moles of Al2O3 can be produced from the previously calculated moles of aluminum. Finally, we can calculate the mass of aluminum oxide that can be formed from the moles of Al2O3 just calculated.
Adi S.
Aluminum reacts with oxygen to give aluminum oxide. $$ 4 \mathrm{Al}(\mathrm{s})+3 \mathrm{O}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{Al}_{2} \mathrm{O}_{3}(\mathrm{s}) $$ What amount of $\mathrm{O}_{2},$ in moles, is needed for complete reaction with 6.0 mol of Al? What mass of $\mathrm{Al}_{2} \mathrm{O}_{3},$ in grams, can be produced?
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