00:01
In this question we have to find integral x cube upon x raised to the power 4 plus 113 x square plus 3196 dx using partial fractions.
00:16
So we have to solve the given integral using the partial fractions.
00:21
So now let us focus on our solution.
00:24
So the integrand can be written as the partial fraction 3196.
00:31
So this can be written as the denominator can be factorized into two factors.
00:36
So let those factors be x square plus a that is ax plus b upon x square plus a plus cx plus d upon x square plus b.
00:48
So x raised to the power 4 plus 113 x square plus 3196 can be factorized as x square plus 64 multiplied by x square plus 49.
01:01
It is 3136.
01:08
So in the given equation it is 3136 3136 over here.
01:16
So if factorizes then it then we get x square plus 64 multiplied by x square plus 49.
01:21
So the given integral can be factorized as x cube divided by x raised to the power 4 plus 113 x square plus 3136 can be written as ax plus b divided by x square plus 64 plus cx plus d divided by x square plus 49.
01:43
So this implies we have ax cube plus 49 ax plus bx square plus 49 b plus cx plus 64 cx plus dx square plus 64 d is equals to x cube...