2. A fiber optic data link (propagation speed is 2 Ă— 10^8m/s) is of length 20km. Packets of length 20 kbits arrive for transmission on the data link at a rate 10^3 per second, and are transmitted at 100 kbit per second. What must the service rate (?) of this data link be that the time each packet spends in the queue awaiting transmission is on average equal to the time spent in transmission?
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The length of each packet is 20 kbits and it is transmitted at a rate of 100 kbit per second. Therefore, the time it takes for a packet to be transmitted is: Time to transmit = Packet length / Transmission rate Time to transmit = 20 kbits / 100 kbit per Show more…
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