2 A ship with displacement: 5500 Tonnes, \( K M_{T}=8.7 \mathrm{~m} \), and \( K G=8.0 \mathrm{~m} \) has a longitudinal double bottom tank that runs its full length between perpendiculars of \( 120 \mathrm{~m} \) which is partly filled with heavy fuel oil of relative density: 0.95 . The surface area of the tank is defined by the following half ordinates: \begin{tabular}{|l|c|c|c|c|c|c|c|c|c|c|c|} \hline Section & AP & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & FP \\ \hline \begin{tabular}{l} Half-Breatth \\ \( (\mathrm{m}) \) \end{tabular} & 0.00 & 1.03 & 1.83 & 2.83 & 3.13 & 3.33 & 2.93 & 1.33 & 1.33 & 0.69 & 0.00 \\ \hline \end{tabular} Determine its resulting Metacentric Height when heeled
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The half ordinates are given at equal intervals of 12m (120m/10). Using Simpson's rule, the volume of the tank (V) is given by: V = (12/3) * [0.00 + 4*(1.03 + 2.83 + 3.33 + 1.33) + 2*(1.83 + 3.13 + 2.93 + 0.69) + 0.00] = 288.96 m^3 Show more…
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