2. Completion ?-Algebras Let $(X, \Sigma, \mu)$ be a measure space and $(X, \bar{\Sigma}, \bar{\mu})$ be its completion measure space. Prove that $\bar{\Sigma} = \{A \triangle B: A \in \Sigma, B \in \mathcal{N}\}$. Recall that $\mathcal{N} = \{B \subset X: B \subset N, N \in \Sigma, \mu(N) = 0\}$ and $\bar{\Sigma} = \{A \cup B: A \in \Sigma, B \in \mathcal{N}\}$.
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Step 1: Recall that the completion measure space X' is defined as the set of all subsets A' of X such that A' = A∪B, where A∈E and B∈N. Show more…
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