Question

2. Evaluate $\int \cos^3 x dx$ a. $\sin x - \cos x + C$ b. $\sin x - \frac{1}{3} \sin^3 x + C$ c. $\sin^2 x + C$

Name: 2 evaluate int cos3 x dx a sin x cos x c b sin x frac13 sin3 x c c sin2 x c 31956
Uploaded: 2019-08-29T00:48:09-08:00
Duration: 20 s
Channel: Amrita Bhasin
Description: 2 evaluate int cos3 x dx a sin x cos x c b sin x frac13 sin3 x c c sin2 x c 31956

          2. Evaluate $\int \cos^3 x dx$
a. $\sin x - \cos x + C$
b. $\sin x - \frac{1}{3} \sin^3 x + C$
c. $\sin^2 x + C$

$2 evaluate int cos3 x dx a sin x cos x c b sin x frac13 sin3 x c c sin2 x c 31956$

Added by Taylor D.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Amrita Bhasin

08/29/2019

Step 1

We can rewrite $\cos^3 x$ as $\cos^2 x \cdot \cos x$. Using the identity $\cos^2 x = 1 - \sin^2 x$, we have: $\int \cos^3 x dx = \int (1 - \sin^2 x) \cos x dx$ Show more…

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